Molecular Basis of Inheritance
🧬 5.1 THE DNA – Core Concept
DNA (Deoxyribonucleic Acid) is the fundamental hereditary molecule found in nearly all living organisms. It stores, transmits, and expresses genetic information and is capable of replication, mutation, and transcription. In some viruses, however, RNA serves as the genetic material.
🎯 Learning Goals:
  • By the end of this section, students should be able to: Identify the chemical structure of DNA
  • Explain the components of a nucleotide
  • Distinguish DNA from RNA
  • Understand how DNA structure relates to function
  • Recall key historical contributions to DNA structure
  • Appreciate the uniqueness and universality of DNA
🧪 5.1.1 Structure of DNA as a Polynucleotide Chain
📚 Background Knowledge:
  • DNA is a polymer of nucleotides
  • Each DNA strand is directional (has 5’ and 3’ ends)
  • The length of DNA is measured in base pairs (bp) or number of nucleotides
📌 Nucleotide Components:
Each nucleotide has 3 parts:
  • Nitrogenous Base
  • Purines: Adenine (A), Guanine (G) → 2 rings
  • Pyrimidines: Cytosine (C), Thymine (T) → 1 ring
  • Pentose Sugar
  • DNA: Deoxyribose (lacks an –OH at 2′ C)
  • RNA: Ribose (has –OH at 2′ C)
  • Phosphate Group
  • Provides negative charge to DNA
  • Links 5′ C of one sugar to 3′ C of another sugar via phosphodiester bond
🔄 Nucleoside vs Nucleotide
🧠 Mnemonic: Nucleoside = Side of Sugar + Base Nucleotide = Tide includes the phosphate ride
🔗 Bonding in DNA
  • Nucleotides are linked by 3′–5′ phosphodiester bonds
  • Direction of DNA strand: 5′ end → phosphate group, 3′ end → free OH group
🧠 Diagram (to draw/describe in class):
🧠 Difference Between DNA and RNA
🧬 DNA LENGTH – A Characteristic Feature
DNA length = number of base pairs (bp)
Examples:
🔍 If each base pair = 0.34 nm apart, then: Human DNA = 3.3 × 10⁹ × 0.34 × 10⁻⁹ m = ~1.12 meters per cell!
📖 5.1.2 Historical Milestone: Discovery of DNA Structure
👨‍🔬 Friedrich Miescher (1869)
  • Isolated an acidic substance from pus cells → called it “nuclein
  • Later identified as DNA
👨‍🔬 Chargaff’s Rule (Erwin Chargaff, 1950)
  • First Parity Rule: In a double-stranded DNA molecule, the amount of adenine (A) is equal to the amount of thymine (T), and the amount of guanine (G) is equal to the amount of cytosine (C).
  • This can be expressed as A = T and G = C.
  • Additionally, the total amount of purines (A+G) equals the total amount of pyrimidines (T+C).
Base Pairing Rule:
  • A = T
  • G ≡ C
  • Total purines = pyrimidines in double-stranded DNA
🔬 Watson & Crick’s Double Helix Model (1953)
Based on:
  • Chargaff’s rules
  • Rosalind Franklin’s X-ray diffraction image
🔥 Salient Features of the Double Helix Model:
  • Two strands wound around each other → Right-handed helix
  • Antiparallel orientation:
  • One strand runs 5’→3’
  • Other strand runs 3’→5’
  • Base Pairing:
  • A = T (via 2 hydrogen bonds)
  • G ≡ C (via 3 hydrogen bonds)
  • Uniform width (2 nm) maintained by pairing 1 purine + 1 pyrimidine
  • One complete turn = 10 base pairs = 3.4 nm
  • Base stacking stabilizes the structure (π–π interactions)
📌 Hydrogen bonds and hydrophobic interactions stabilize the double helix 🧠 Mnemonic to remember base bonds: “AT2 (A–T has 2 bonds) & GC3 (G–C has 3 bonds)”
🔁 Complementarity of DNA Strands
  • Each strand is complementary, not identical.
  • If you know one strand, the other can be predicted.
Example: If one strand is: 5′ – ATCGGCTA – 3′ Then the complementary strand is: 3′ – TAGCCGAT – 5′
🧠 Importance: This complementarity is the basis for:
  • DNA Replication
  • Transcription
  • DNA Fingerprinting
  • PCR amplification
Visit: DNA DOUBLE HELIX 3D BY PERSUEAI unknown link
🔁 Summary of Key Terminologies
📌 Application-Based Questions (For NEET & JENPAS)
  • Why is DNA more stable than RNA? → Absence of 2'-OH group, double-stranded nature, use of thymine.
  • If a DNA molecule has 20% cytosine, what is the % of adenine? → Cytosine = Guanine = 20%, So A + T = 60%, ⇒ A = 30%
  • Which base pairs are stronger? → G–C (3 hydrogen bonds) are stronger than A–T (2 hydrogen bonds)
🧬 5.2 THE SEARCH FOR GENETIC MATERIAL
🧪 Step-by-Step Experimental Proofs that DNA is Genetic Material
🔬 1. Griffith’s Transformation Experiment (1928)
🧠 Objective: To determine if a chemical substance from dead bacteria could transform living bacteria.
🔍 Bacteria Used: Streptococcus pneumoniae (causes pneumonia)
  • S strain (Smooth): Has polysaccharide capsule → virulent
  • R strain (Rough): No capsule → non-virulent
🔬 Experimental Steps:
🔍 Interpretation:
  • Some "transforming principle" from dead S strain converted R strain into S strain
  • Demonstrated transfer of genetic material without knowing its exact nature
📝 Conclusion: Transformation is real and inheritable. The chemical identity (DNA, RNA, or protein?) was still unknown.
🔬 2. Avery, MacLeod, McCarty Experiment (1944)
🧠 Objective: To identify the chemical nature of Griffith’s “transforming principle”
🔬 Method:
  • Extracted biomolecules (DNA, RNA, proteins) from heat-killed S strain
  • Treated them with specific enzymes to isolate effects:
  • Protease → Destroys proteins
  • RNase → Destroys RNA
  • DNase → Destroys DNA
  • Mixed each treated extract with live R strain and injected into mice
📊 Observations:
📝 Conclusion: Only DNA destruction blocked transformation DNA is the hereditary substance, not proteins or RNA Significance: First biochemical proof that DNA is the genetic material, not widely accepted immediately due to protein-bias in science at the time.
🔬 3. Hershey–Chase Experiment (1952)
🧠 Objective: To confirm whether DNA or protein is transferred by viruses into host cells.
🔬 Organisms Used: Bacteriophage T2 (a virus that infects E. coli)
Components of virus:
  • DNA (contains phosphorus)
  • Protein coat (contains sulfur)
🔬 Experiment Setup:
🧫 Procedure:
  • Grow two batches of phage:
  • One with ³²P (labels DNA)
  • One with ³⁵S (labels protein)
  • Allow each phage type to infect E. coli
  • Use blender to separate viral coats from infected bacteria
  • Centrifuge the solution
  • Bacterial pellet = host cell content
  • Supernatant = viral protein coats
  • Measure radioactivity in each layer
🔍 Observations:
📝 Conclusion: Only DNA enters host and directs viral replication Final conclusive proof that DNA is the genetic material
🧬 5.2.2 Properties of Genetic Material
A molecule to qualify as genetic material must meet the following 4 essential criteria:
⚖️ DNA vs RNA – Which is Better as Genetic Material?
DNA is chemically and structurally more stable, hence preferred for genetic storage
📊 Summary Table of Key Experiments
📌 HOTS (Higher Order Thinking) for NEET / JENPAS
  • Why did ³²P label DNA and not protein? → DNA contains phosphorus; proteins do not.
  • Why is RNA less stable than DNA? → Presence of reactive 2'-OH group in ribose makes RNA prone to hydrolysis.
  • What if both DNA and protein entered the host cell? → Then both could potentially be considered genetic materials. But only DNA enters.
🧬 5.3 – The RNA World
🎯 Target Exams: NEET UG | JENPAS UG | CBSE/WBCHSE Boards
🎯 Learning Objectives:
By the end of this section, learners should be able to:
  • Understand the concept of the RNA World Hypothesis
  • Explain why RNA was likely the first genetic material
  • Describe the dual functions of RNA: genetic storage and catalysis
  • Realize the evolutionary transition from RNA to DNA and proteins
  • Understand the role of ribozymes and modern RNA examples
🧠 Core Concept: What is the RNA World Hypothesis?
RNA World Hypothesis proposes that early life forms on Earth may have relied solely on RNA to:
  • Store genetic information
  • Catalyze biochemical reactions
🌍 Hypothesis Background:
  • Proposed in the 1960s and expanded by Walter Gilbert in 1986.
  • Originated from studies on self-replicating RNA molecules.
🔎 Scientific Basis: Why is RNA believed to be the first genetic material?
🧪 Evidence Supporting RNA World
🔹 1. Ribozymes
  • Definition: Catalytic RNA molecules that act like enzymes
  • First discovered by Thomas Cech and Sidney Altman
  • Capable of:
  • Cutting/joining RNA
  • Peptide bond formation (as in rRNA of ribosomes)
🧠 NEET Alert: Large rRNA (23S in prokaryotes; 28S in eukaryotes) acts as ribozyme in protein synthesis.
🔹 2. Self-Replication Ability
  • Laboratory experiments (e.g., Spiegelman’s Monster, in vitro evolution)
  • Show RNA strands can replicate and evolve under appropriate conditions
🔹 3. Viroids: Natural Proof of RNA’s Capability
  • Viroids are infectious RNA molecules found in plants
  • Lack protein coat, yet replicate independently
  • Use host machinery, but do not require DNA or protein
📌 Example: Potato spindle tuber viroid
🔹 4. RNA in Modern Biology – A Living Fossil
🧠 These show RNA’s versatility and ancient origin.
⚖️ RNA vs DNA vs Protein in Early Life
🔁 Transition from RNA World → DNA-Protein World
Hypothesized Sequence:
  • RNA molecules emerged from prebiotic soup
  • Self-replicating RNA evolved
  • Catalytic RNAs (ribozymes) enabled complex reactions
  • Proteins took over catalytic roles (more efficient)
  • DNA evolved as a stable genetic storehouse (double-stranded, proofreading)
🧠 Mnemonic: “R → R/P → P → D” RNA → RNA/Protein → Protein → DNA
🧬 Evolutionary Advantage of DNA:
📌 Thymine in DNA (instead of Uracil) further reduces mutation by detecting deamination of cytosine → uracil
📚 Summary of Key Concepts
🧪 Important Questions – NEET & JENPAS Pattern
  • Which of the following molecules is both catalytic and genetic in early life? a) DNA b) Protein c) RNA d) Lipid
  • The RNA molecule that acts as an enzyme is called: a) Viroid b) Ribozyme c) SnRNA d) Ribosome
  • Which RNA acts as ribozyme in protein synthesis? a) mRNA b) tRNA c) 23S rRNA d) 16S rRNA
  • RNA is believed to be the first genetic material because it can: a) Mutate b) Replicate c) Catalyse reactions d) All of these
🧠 Concept Map (Visual Summary)
🧬 Section 5.4 – DNA Replication
📘 Chapter: Molecular Basis of Inheritance
🎯 Target Exams: NEET UG, JENPAS UG, CBSE/WBCHSE Boards
🎯 Learning Objectives
By the end of this topic, students should be able to:
  • Understand the semiconservative nature of DNA replication
  • Explain the experimental proof (Meselson-Stahl experiment)
  • Describe the enzymes involved and their specific roles
  • Differentiate between leading and lagging strand synthesis
  • Understand the directionality and mechanism of DNA replication
  • Apply knowledge to NEET-style questions and diagrams
🔍 What is DNA Replication?
Definition: DNA replication is the biological process of producing two identical copies of DNA from one original DNA molecule. It ensures genetic continuity across generations of cells.
🔄 Key Features of DNA Replication:
🔬 Semiconservative Model of DNA Replication
🧠 Proposed by: Watson and Crick (1953) immediately after proposing the double-helix structure
যখন একটি ডিএনএ অণু প্রতিলিপি করে, তখন এটি দুটি স্ট্র্যান্ডে বিভক্ত হয়ে যায়। প্রতিটি স্ট্র্যান্ড একটি নতুন স্ট্র্যান্ড তৈরির জন্য একটি টেমপ্লেট হিসেবে কাজ করে। এই প্রক্রিয়ার শেষে, দুটি নতুন ডিএনএ অণু তৈরি হয়, যেখানে প্রতিটি অণুতে একটি পুরনো এবং একটি নতুন স্ট্র্যান্ড থাকে। এই কারণেই একে "অর্ধ-সংরক্ষণশীল" বলা হয়।
🧪 Proven by: Meselson and Stahl Experiment (1958)
🧪 Meselson–Stahl Experiment – Definitive Proof
🧪 Organism Used: Escherichia coli
🧪 Isotopes Used:
  • 15N (heavy nitrogen – used to label parental DNA)
  • 14N (normal nitrogen – used in new DNA synthesis)
🧬 Procedure:
  • Grew E. coli for many generations in 15N medium → DNA becomes heavy
  • Transferred to 14N medium, and allowed DNA to replicate
  • Took samples after 1st and 2nd generation of replication
  • Separated DNA by centrifugation in cesium chloride (CsCl) gradient
🔍 Observations:
🧾 Conclusion: Each new DNA molecule has one parental strand and one newly synthesized strand Confirmed semiconservative replication in E. coli One of the most elegant and classic proofs in molecular biology
🧠 NEET Tip: Conservative and dispersive models were disproven by this experiment.
এই পরীক্ষার ফলাফল থেকে মেসেলসন ও স্টাহল এই সিদ্ধান্তে উপনীত হন যে ডিএনএ অণুগুলো সেমি-কনজারভেটিভ পদ্ধতিতে প্রতিলিপি করে. এই পদ্ধতিতে, ডিএনএর দুটি স্ট্র্যান্ড আলাদা হয়ে যায় এবং প্রতিটি স্ট্র্যান্ড একটি নতুন পরিপূরক স্ট্র্যান্ড তৈরির জন্য টেমপ্লেট হিসাবে কাজ করে. এর ফলে উৎপন্ন প্রতিটি ডিএনএ অণুতে একটি পুরনো স্ট্র্যান্ড এবং একটি নতুন স্ট্র্যান্ড থাকে
🧬 Enzymes & Proteins Involved in DNA Replication
🧠 In prokaryotes: DNA Polymerase III = main synthesizing enzyme
DNA Polymerase I = fills in primer gaps + proofreads
🔄 Leading vs Lagging Strand
🧠 Okazaki Fragments: Short fragments (~1000–2000 bp in prokaryotes) formed during lagging strand synthesis
🔂 Direction of Replication
  • DNA is antiparallel, so:
  • Replication moves 5′ → 3′
  • Template strand read 3′ → 5′
  • Replication fork proceeds bidirectionally in prokaryotes
🧠 NEET Tip: DNA polymerase cannot initiate synthesis → needs RNA primer to begin
📊 DNA Replication in Prokaryotes vs Eukaryotes
🧬 Summary Diagram: DNA Replication Fork
5' ——————————————→ 3' (leading strand) | | Helicase DNA pol III | | 3' ————————————→ 5' ←————————— 5' (lagging strand; Okazaki fragments) ↑ RNA Primer
(Draw an annotated fork showing helicase, primase, polymerases, ligase)
🧾 Key Characteristics of DNA Polymerase:
  • Adds nucleotides only in 5′ → 3′ direction
  • Requires:
  • Template strand
  • RNA primer
  • Free 3′ OH group
  • Has proofreading (3′ → 5′ exonuclease) activity for error correction
🧠 Error rate: ~1 in 10⁷ base insertions; further reduced by proofreading
Summary Table – DNA Replication at a Glance
📚 Practice Questions – NEET/JENPAS Style
  • Which enzyme joins Okazaki fragments? a) DNA pol I b) Ligase c) Helicase d) Primase
  • DNA replication is termed ‘semiconservative’ because: a) New DNA contains two new strands b) One strand is old, one is new c) One is DNA, one is RNA d) Both strands are new
  • Which of the following has exonuclease activity (proofreading)? a) DNA pol III b) DNA pol I c) Both d) None
  • Why does lagging strand synthesis need multiple primers? → Because it is synthesized discontinuously as Okazaki fragments
🧠 Memory Aids and Mnemonics
🧠 "He Took Pretty Long Slides"
  • Helicase – Unwinds
  • Topoisomerase – Releases supercoiling
  • Primase – Synthesizes primers
  • Ligase – Joins fragments
  • SSBPs – Stabilize strands
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